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50x+5x^2=7x
We move all terms to the left:
50x+5x^2-(7x)=0
We add all the numbers together, and all the variables
5x^2+43x=0
a = 5; b = 43; c = 0;
Δ = b2-4ac
Δ = 432-4·5·0
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1849}=43$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-43}{2*5}=\frac{-86}{10} =-8+3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+43}{2*5}=\frac{0}{10} =0 $
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